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51747174113 = 269192368677
BaseRepresentation
bin110000001100010111…
…110011011011100001
311221120100102210221012
4300030113303123201
51321434234032423
635434453310305
73511225502555
oct601427633341
9157510383835
1051747174113
111aa44a268a8
12a042035395
134b58a2536b
14270c7b5865
15152ce66078
hexc0c5f36e1

51747174113 has 4 divisors (see below), whose sum is σ = 51939543060. Its totient is φ = 51554805168.

The previous prime is 51747174109. The next prime is 51747174121. The reversal of 51747174113 is 31147174715.

51747174113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23283097744 + 28464076369 = 152588^2 + 168713^2 .

It is a cyclic number.

It is not a de Polignac number, because 51747174113 - 22 = 51747174109 is a prime.

It is a super-2 number, since 2×517471741132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51747174133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96184070 + ... + 96184607.

It is an arithmetic number, because the mean of its divisors is an integer number (12984885765).

Almost surely, 251747174113 is an apocalyptic number.

It is an amenable number.

51747174113 is a deficient number, since it is larger than the sum of its proper divisors (192368947).

51747174113 is a wasteful number, since it uses less digits than its factorization.

51747174113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192368946.

The product of its digits is 82320, while the sum is 41.

The spelling of 51747174113 in words is "fifty-one billion, seven hundred forty-seven million, one hundred seventy-four thousand, one hundred thirteen".

Divisors: 1 269 192368677 51747174113