Base | Representation |
---|---|
bin | 1001101001110011… |
… | …10100100110100101 |
3 | 111101011212022122020 |
4 | 10310321310212211 |
5 | 41103212241242 |
6 | 2214131453353 |
7 | 242266602432 |
oct | 46471644645 |
9 | 14334768566 |
10 | 5182540197 |
11 | 221a45517a |
12 | 1007757259 |
13 | 647911a43 |
14 | 37241ab89 |
15 | 204eb26ec |
hex | 134e749a5 |
5182540197 has 4 divisors (see below), whose sum is σ = 6910053600. Its totient is φ = 3455026796.
The previous prime is 5182540193. The next prime is 5182540199. The reversal of 5182540197 is 7910452815.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5182540197 - 22 = 5182540193 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5182540193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 863756697 + ... + 863756702.
It is an arithmetic number, because the mean of its divisors is an integer number (1727513400).
Almost surely, 25182540197 is an apocalyptic number.
It is an amenable number.
5182540197 is a deficient number, since it is larger than the sum of its proper divisors (1727513403).
5182540197 is a wasteful number, since it uses less digits than its factorization.
5182540197 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1727513402.
The product of its (nonzero) digits is 100800, while the sum is 42.
The square root of 5182540197 is about 71989.8617653903. The cubic root of 5182540197 is about 1730.5370153947.
The spelling of 5182540197 in words is "five billion, one hundred eighty-two million, five hundred forty thousand, one hundred ninety-seven".
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