Base | Representation |
---|---|
bin | 110000010001011011… |
… | …011110000011011101 |
3 | 11221210021002111021101 |
4 | 300101123132003131 |
5 | 1322122444134323 |
6 | 35451124033101 |
7 | 3513305624320 |
oct | 602133360335 |
9 | 157707074241 |
10 | 51832021213 |
11 | 1aa88908775 |
12 | a066532791 |
13 | 4b70491a4b |
14 | 2719b807b7 |
15 | 1535625dad |
hex | c116de0dd |
51832021213 has 4 divisors (see below), whose sum is σ = 59236595680. Its totient is φ = 44427446748.
The previous prime is 51832021211. The next prime is 51832021217. The reversal of 51832021213 is 31212023815.
51832021213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51832021213 - 21 = 51832021211 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51832021211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3702287223 + ... + 3702287236.
It is an arithmetic number, because the mean of its divisors is an integer number (14809148920).
Almost surely, 251832021213 is an apocalyptic number.
It is an amenable number.
51832021213 is a deficient number, since it is larger than the sum of its proper divisors (7404574467).
51832021213 is an equidigital number, since it uses as much as digits as its factorization.
51832021213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7404574466.
The product of its (nonzero) digits is 2880, while the sum is 28.
The spelling of 51832021213 in words is "fifty-one billion, eight hundred thirty-two million, twenty-one thousand, two hundred thirteen".
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