Base | Representation |
---|---|
bin | 100101101101101101011… |
… | …0011100101001011100101 |
3 | 200100112021011102100020210 |
4 | 1023123122303211023211 |
5 | 1134411101241414301 |
6 | 15005115523250033 |
7 | 1043326343622615 |
oct | 113333263451345 |
9 | 20315234370223 |
10 | 5183401513701 |
11 | 17192a5029294 |
12 | 6b86b2819919 |
13 | 2b7a3c6415c8 |
14 | 13cc41224a45 |
15 | 8ec73880ad6 |
hex | 4b6dace52e5 |
5183401513701 has 16 divisors (see below), whose sum is σ = 6996038224896. Its totient is φ = 3413201581296.
The previous prime is 5183401513649. The next prime is 5183401513709. The reversal of 5183401513701 is 1073151043815.
It is not a de Polignac number, because 5183401513701 - 225 = 5183367959269 is a prime.
It is a super-3 number, since 3×51834015137013 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5183401513701.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5183401513709) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1220875 + ... + 3443448.
It is an arithmetic number, because the mean of its divisors is an integer number (437252389056).
Almost surely, 25183401513701 is an apocalyptic number.
It is an amenable number.
5183401513701 is a deficient number, since it is larger than the sum of its proper divisors (1812636711195).
5183401513701 is a wasteful number, since it uses less digits than its factorization.
5183401513701 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4668872.
The product of its (nonzero) digits is 50400, while the sum is 39.
The spelling of 5183401513701 in words is "five trillion, one hundred eighty-three billion, four hundred one million, five hundred thirteen thousand, seven hundred one".
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