Base | Representation |
---|---|
bin | 110000010110001110… |
… | …000110101101010111 |
3 | 11221222212100100110012 |
4 | 300112032012231113 |
5 | 1322304033410144 |
6 | 35503114550435 |
7 | 3515303103014 |
oct | 602616065527 |
9 | 157885310405 |
10 | 51912403799 |
11 | 2001a220363 |
12 | a08943841b |
13 | 4b840272c9 |
14 | 272670670b |
15 | 153c702e9e |
hex | c16386b57 |
51912403799 has 4 divisors (see below), whose sum is σ = 52687215864. Its totient is φ = 51137591736.
The previous prime is 51912403789. The next prime is 51912403811. The reversal of 51912403799 is 99730421915.
51912403799 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51912403799 - 24 = 51912403783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51912403769) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387405932 + ... + 387406065.
It is an arithmetic number, because the mean of its divisors is an integer number (13171803966).
Almost surely, 251912403799 is an apocalyptic number.
51912403799 is a deficient number, since it is larger than the sum of its proper divisors (774812065).
51912403799 is an equidigital number, since it uses as much as digits as its factorization.
51912403799 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 774812064.
The product of its (nonzero) digits is 612360, while the sum is 50.
The spelling of 51912403799 in words is "fifty-one billion, nine hundred twelve million, four hundred three thousand, seven hundred ninety-nine".
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