Base | Representation |
---|---|
bin | 100101110101011111001… |
… | …0111110110010110101111 |
3 | 200102010101012202101210001 |
4 | 1023222332113312112233 |
5 | 1140144303203214101 |
6 | 15020521151125131 |
7 | 1044460301452663 |
oct | 113527627662657 |
9 | 20363335671701 |
10 | 5200104351151 |
11 | 1725396381286 |
12 | 6bb9945137a7 |
13 | 2b94a1bbb588 |
14 | 13d98766c8a3 |
15 | 903eee09901 |
hex | 4babe5f65af |
5200104351151 has 4 divisors (see below), whose sum is σ = 5200109197704. Its totient is φ = 5200099504600.
The previous prime is 5200104351083. The next prime is 5200104351257. The reversal of 5200104351151 is 1511534010025.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 5200104351151 - 223 = 5200095962543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5200104351551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18145 + ... + 3224986.
It is an arithmetic number, because the mean of its divisors is an integer number (1300027299426).
Almost surely, 25200104351151 is an apocalyptic number.
5200104351151 is a deficient number, since it is larger than the sum of its proper divisors (4846553).
5200104351151 is a wasteful number, since it uses less digits than its factorization.
5200104351151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4846552.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 5200104351151 its reverse (1511534010025), we get a palindrome (6711638361176).
The spelling of 5200104351151 in words is "five trillion, two hundred billion, one hundred four million, three hundred fifty-one thousand, one hundred fifty-one".
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