Base | Representation |
---|---|
bin | 10111101001100001010111… |
… | …11101010100100001101001 |
3 | 20211010112221012220012022210 |
4 | 23310300223331110201221 |
5 | 23304014101041440423 |
6 | 302334222251235333 |
7 | 13645115410260321 |
oct | 1364605375244151 |
9 | 224115835805283 |
10 | 52004201515113 |
11 | 1562a949010411 |
12 | 59ba919a48b49 |
13 | 2302c8a573863 |
14 | cbb0340a6281 |
15 | 602b3691ab93 |
hex | 2f4c2bf54869 |
52004201515113 has 16 divisors (see below), whose sum is σ = 69380229672000. Its totient is φ = 34648821366720.
The previous prime is 52004201515111. The next prime is 52004201515139. The reversal of 52004201515113 is 31151510240025.
It is not a de Polignac number, because 52004201515113 - 21 = 52004201515111 is a prime.
It is a super-3 number, since 3×520042015151133 (a number of 42 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (52004201515111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 374414443 + ... + 374553311.
It is an arithmetic number, because the mean of its divisors is an integer number (4336264354500).
Almost surely, 252004201515113 is an apocalyptic number.
It is an amenable number.
52004201515113 is a deficient number, since it is larger than the sum of its proper divisors (17376028156887).
52004201515113 is a wasteful number, since it uses less digits than its factorization.
52004201515113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212312.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 52004201515113 its reverse (31151510240025), we get a palindrome (83155711755138).
The spelling of 52004201515113 in words is "fifty-two trillion, four billion, two hundred one million, five hundred fifteen thousand, one hundred thirteen".
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