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52004354471 = 193912681881
BaseRepresentation
bin110000011011101100…
…110111100110100111
311222020021100221001122
4300123230313212213
51323001103320341
635520201444155
73520500501536
oct603354674647
9158207327048
1052004354471
1120067114253
12a0b41a065b
134b9a0b00a4
142734a0031d
15154581794b
hexc1bb379a7

52004354471 has 4 divisors (see below), whose sum is σ = 52007055744. Its totient is φ = 52001653200.

The previous prime is 52004354443. The next prime is 52004354473. The reversal of 52004354471 is 17445340025.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52004354471 - 210 = 52004353447 is a prime.

It is a super-3 number, since 3×520043544713 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52004354473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321550 + ... + 1360331.

It is an arithmetic number, because the mean of its divisors is an integer number (13001763936).

Almost surely, 252004354471 is an apocalyptic number.

52004354471 is a deficient number, since it is larger than the sum of its proper divisors (2701273).

52004354471 is a wasteful number, since it uses less digits than its factorization.

52004354471 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2701272.

The product of its (nonzero) digits is 67200, while the sum is 35.

Adding to 52004354471 its reverse (17445340025), we get a palindrome (69449694496).

The spelling of 52004354471 in words is "fifty-two billion, four million, three hundred fifty-four thousand, four hundred seventy-one".

Divisors: 1 19391 2681881 52004354471