Base | Representation |
---|---|
bin | 10111101001100011000100… |
… | …11011111010101101011111 |
3 | 20211010122021220201201102201 |
4 | 23310301202123322231133 |
5 | 23304022434032134003 |
6 | 302334453101232331 |
7 | 13645150146125326 |
oct | 1364614233725537 |
9 | 224118256651381 |
10 | 52005115505503 |
11 | 15630277a28976 |
12 | 59bab33b626a7 |
13 | 23030a4a28184 |
14 | cbb0bd6250bd |
15 | 602b8bcacb1d |
hex | 2f4c626fab5f |
52005115505503 has 4 divisors (see below), whose sum is σ = 52005220690248. Its totient is φ = 52005010320760.
The previous prime is 52005115505489. The next prime is 52005115505587. The reversal of 52005115505503 is 30550551150025.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52005115505503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52005115305503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51847228 + ... + 52840753.
It is an arithmetic number, because the mean of its divisors is an integer number (13001305172562).
Almost surely, 252005115505503 is an apocalyptic number.
52005115505503 is a deficient number, since it is larger than the sum of its proper divisors (105184745).
52005115505503 is a wasteful number, since it uses less digits than its factorization.
52005115505503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105184744.
The product of its (nonzero) digits is 93750, while the sum is 37.
Adding to 52005115505503 its reverse (30550551150025), we get a palindrome (82555666655528).
The spelling of 52005115505503 in words is "fifty-two trillion, five billion, one hundred fifteen million, five hundred five thousand, five hundred three".
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