Base | Representation |
---|---|
bin | 10111101011101111100010… |
… | …10011111101010111001101 |
3 | 20211101211221110202211020112 |
4 | 23311313301103331113031 |
5 | 23311241404403131013 |
6 | 302433244103325405 |
7 | 13653460003240664 |
oct | 1365676123752715 |
9 | 224354843684215 |
10 | 52080527005133 |
11 | 1565a255837790 |
12 | 5a1167b150865 |
13 | 230a23233acc3 |
14 | cc09d4c17ddb |
15 | 604b0250aba8 |
hex | 2f5df14fd5cd |
52080527005133 has 8 divisors (see below), whose sum is σ = 58136402238816. Its totient is φ = 46244865416400.
The previous prime is 52080527005127. The next prime is 52080527005147. The reversal of 52080527005133 is 33150072508025.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 52080527005133 - 222 = 52080522810829 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52080527005103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55053410738 + ... + 55053411683.
It is an arithmetic number, because the mean of its divisors is an integer number (7267050279852).
Almost surely, 252080527005133 is an apocalyptic number.
It is an amenable number.
52080527005133 is a deficient number, since it is larger than the sum of its proper divisors (6055875233683).
52080527005133 is a wasteful number, since it uses less digits than its factorization.
52080527005133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110106822475.
The product of its (nonzero) digits is 252000, while the sum is 41.
The spelling of 52080527005133 in words is "fifty-two trillion, eighty billion, five hundred twenty-seven million, five thousand, one hundred thirty-three".
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