Base | Representation |
---|---|
bin | 10111101011110100100111… |
… | …11001100111001011000111 |
3 | 20211102002222120120101100210 |
4 | 23311322103321213023013 |
5 | 23311313001211102321 |
6 | 302434414505210503 |
7 | 13653614415054063 |
oct | 1365722371471307 |
9 | 224362876511323 |
10 | 52083254784711 |
11 | 15660425577977 |
12 | 5a12100790a33 |
13 | 230a5784ccb67 |
14 | cc0bb31dcaa3 |
15 | 604c11c2bb76 |
hex | 2f5e93e672c7 |
52083254784711 has 8 divisors (see below), whose sum is σ = 69445632661120. Its totient is φ = 34721523382392.
The previous prime is 52083254784689. The next prime is 52083254784719. The reversal of 52083254784711 is 11748745238025.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-52083254784711 is a prime.
It is a super-3 number, since 3×520832547847113 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52083254784719) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161430505 + ... + 161752818.
It is an arithmetic number, because the mean of its divisors is an integer number (8680704082640).
Almost surely, 252083254784711 is an apocalyptic number.
52083254784711 is a deficient number, since it is larger than the sum of its proper divisors (17362377876409).
52083254784711 is a wasteful number, since it uses less digits than its factorization.
52083254784711 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 323237045.
The product of its (nonzero) digits is 15052800, while the sum is 57.
The spelling of 52083254784711 in words is "fifty-two trillion, eighty-three billion, two hundred fifty-four million, seven hundred eighty-four thousand, seven hundred eleven".
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