Base | Representation |
---|---|
bin | 110000100001100111… |
… | …000000011111110111 |
3 | 11222111011220002112222 |
4 | 300201213000133313 |
5 | 1323201442400320 |
6 | 35534102232555 |
7 | 3523113166253 |
oct | 604147003767 |
9 | 158434802488 |
10 | 52103481335 |
11 | 20108069784 |
12 | a12142575b |
13 | 4bb47a9339 |
14 | 2743c45263 |
15 | 154e398825 |
hex | c219c07f7 |
52103481335 has 4 divisors (see below), whose sum is σ = 62524177608. Its totient is φ = 41682785064.
The previous prime is 52103481317. The next prime is 52103481361. The reversal of 52103481335 is 53318430125.
52103481335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52103481335 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52103481295 and 52103481304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5210348129 + ... + 5210348138.
It is an arithmetic number, because the mean of its divisors is an integer number (15631044402).
Almost surely, 252103481335 is an apocalyptic number.
52103481335 is a deficient number, since it is larger than the sum of its proper divisors (10420696273).
52103481335 is a wasteful number, since it uses less digits than its factorization.
52103481335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10420696272.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 52103481335 in words is "fifty-two billion, one hundred three million, four hundred eighty-one thousand, three hundred thirty-five".
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