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52110344250013 = 77444334892859
BaseRepresentation
bin10111101100100111000101…
…00011101110001010011101
320211111200220111011210201111
423312103202203232022131
523312233441112000023
6302455054530342021
713655563623525040
oct1366234243561235
9224450814153644
1052110344250013
11156709668a7125
125a17400a2a911
13230cca48a617a
14cc2222c8cc57
1560579a08500d
hex2f64e28ee29d

52110344250013 has 4 divisors (see below), whose sum is σ = 59554679142880. Its totient is φ = 44666009357148.

The previous prime is 52110344249987. The next prime is 52110344250043. The reversal of 52110344250013 is 31005244301125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52110344250013 - 225 = 52110310695581 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52110344250043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3722167446423 + ... + 3722167446436.

It is an arithmetic number, because the mean of its divisors is an integer number (14888669785720).

Almost surely, 252110344250013 is an apocalyptic number.

It is an amenable number.

52110344250013 is a deficient number, since it is larger than the sum of its proper divisors (7444334892867).

52110344250013 is an equidigital number, since it uses as much as digits as its factorization.

52110344250013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7444334892866.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 52110344250013 its reverse (31005244301125), we get a palindrome (83115588551138).

The spelling of 52110344250013 in words is "fifty-two trillion, one hundred ten billion, three hundred forty-four million, two hundred fifty thousand, thirteen".

Divisors: 1 7 7444334892859 52110344250013