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52120342541 = 71277313083
BaseRepresentation
bin110000100010100111…
…010101000000001101
311222112100121201210002
4300202213111000031
51323220301430131
635535503454045
73523406413301
oct604247250015
9158470551702
1052120342541
1120116635863
12a126bb7325
134bb8130b97
142746193d01
151550ac96cb
hexc229d500d

52120342541 has 4 divisors (see below), whose sum is σ = 52127662752. Its totient is φ = 52113022332.

The previous prime is 52120342513. The next prime is 52120342577. The reversal of 52120342541 is 14524302125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52120342541 - 214 = 52120326157 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52120342511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3649415 + ... + 3663668.

It is an arithmetic number, because the mean of its divisors is an integer number (13031915688).

Almost surely, 252120342541 is an apocalyptic number.

It is an amenable number.

52120342541 is a deficient number, since it is larger than the sum of its proper divisors (7320211).

52120342541 is an equidigital number, since it uses as much as digits as its factorization.

52120342541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7320210.

The product of its (nonzero) digits is 9600, while the sum is 29.

Adding to 52120342541 its reverse (14524302125), we get a palindrome (66644644666).

The spelling of 52120342541 in words is "fifty-two billion, one hundred twenty million, three hundred forty-two thousand, five hundred forty-one".

Divisors: 1 7127 7313083 52120342541