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52124935 = 510424987
BaseRepresentation
bin1100011011010…
…1110100000111
310122002012222011
43012311310013
5101320444220
65101115051
71202024512
oct306656407
9118065864
1052124935
1127472265
1215558a87
13aa50675
146ccbd79
15489965a
hex31b5d07

52124935 has 4 divisors (see below), whose sum is σ = 62549928. Its totient is φ = 41699944.

The previous prime is 52124929. The next prime is 52124951. The reversal of 52124935 is 53942125.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52124935 - 25 = 52124903 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52124897 and 52124906.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5212489 + ... + 5212498.

It is an arithmetic number, because the mean of its divisors is an integer number (15637482).

Almost surely, 252124935 is an apocalyptic number.

52124935 is a deficient number, since it is larger than the sum of its proper divisors (10424993).

52124935 is a wasteful number, since it uses less digits than its factorization.

52124935 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10424992.

The product of its digits is 10800, while the sum is 31.

The square root of 52124935 is about 7219.7600375636. The cubic root of 52124935 is about 373.5498005013.

It can be divided in two parts, 521249 and 35, that added together give a square (521284 = 7222).

The spelling of 52124935 in words is "fifty-two million, one hundred twenty-four thousand, nine hundred thirty-five".

Divisors: 1 5 10424987 52124935