Base | Representation |
---|---|
bin | 110000100011010000… |
… | …011001111010000111 |
3 | 11222120002212210200200 |
4 | 300203100121322013 |
5 | 1323231031014120 |
6 | 35540530341543 |
7 | 3523600062000 |
oct | 604320317207 |
9 | 158502783620 |
10 | 52131110535 |
11 | 2012171aa29 |
12 | a12a72a8b3 |
13 | 4bba43118a |
14 | 27477981a7 |
15 | 1551a04e90 |
hex | c23419e87 |
52131110535 has 192 divisors, whose sum is σ = 107726112000. Its totient is φ = 23307153408.
The previous prime is 52131110497. The next prime is 52131110543. The reversal of 52131110535 is 53501113125.
52131110535 is a `hidden beast` number, since 5 + 2 + 13 + 1 + 110 + 535 = 666.
It is not a de Polignac number, because 52131110535 - 215 = 52131077767 is a prime.
It is a super-2 number, since 2×521311105352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52131110499 and 52131110508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 188198817 + ... + 188199093.
It is an arithmetic number, because the mean of its divisors is an integer number (561073500).
Almost surely, 252131110535 is an apocalyptic number.
52131110535 is an abundant number, since it is smaller than the sum of its proper divisors (55595001465).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
52131110535 is a wasteful number, since it uses less digits than its factorization.
52131110535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 535 (or 518 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
The spelling of 52131110535 in words is "fifty-two billion, one hundred thirty-one million, one hundred ten thousand, five hundred thirty-five".
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