Base | Representation |
---|---|
bin | 100101111011101001010… |
… | …1100100010100100100111 |
3 | 200110101111221120012220111 |
4 | 1023313102230202210213 |
5 | 1140403400014040401 |
6 | 15030545411313451 |
7 | 1045436116503220 |
oct | 113672254424447 |
9 | 20411457505814 |
10 | 5213330221351 |
11 | 172aa62aa931a |
12 | 7024658ab887 |
13 | 2ba7cc004885 |
14 | 14047ddd2247 |
15 | 909260c5e51 |
hex | 4bdd2b22927 |
5213330221351 has 4 divisors (see below), whose sum is σ = 5958091681552. Its totient is φ = 4468568761152.
The previous prime is 5213330221327. The next prime is 5213330221417. The reversal of 5213330221351 is 1531220333125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5213330221351 - 217 = 5213330090279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5213330221651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 372380730090 + ... + 372380730103.
It is an arithmetic number, because the mean of its divisors is an integer number (1489522920388).
Almost surely, 25213330221351 is an apocalyptic number.
5213330221351 is a deficient number, since it is larger than the sum of its proper divisors (744761460201).
5213330221351 is an equidigital number, since it uses as much as digits as its factorization.
5213330221351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 744761460200.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 5213330221351 its reverse (1531220333125), we get a palindrome (6744550554476).
The spelling of 5213330221351 in words is "five trillion, two hundred thirteen billion, three hundred thirty million, two hundred twenty-one thousand, three hundred fifty-one".
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