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52141225117642 = 226070612558821
BaseRepresentation
bin10111101101100000100110…
…01100111000011111001010
320211121122121121222102022121
423312300103030320133022
523313240212112231032
6302521203110441454
713661036110546063
oct1366602314703712
9224548547872277
1052141225117642
1115682a73295031
125a2139a96328a
132312b865c63cb
14cc39122b356a
156064a61aba97
hex2f6c133387ca

52141225117642 has 4 divisors (see below), whose sum is σ = 78211837676466. Its totient is φ = 26070612558820.

The previous prime is 52141225117621. The next prime is 52141225117643. The reversal of 52141225117642 is 24671152214125.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 35922893332041 + 16218331785601 = 5993571^2 + 4027199^2 .

It is a super-3 number, since 3×521412251176423 (a number of 42 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (52141225117643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13035306279409 + ... + 13035306279412.

Almost surely, 252141225117642 is an apocalyptic number.

52141225117642 is a deficient number, since it is larger than the sum of its proper divisors (26070612558824).

52141225117642 is a wasteful number, since it uses less digits than its factorization.

52141225117642 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26070612558823.

The product of its digits is 268800, while the sum is 43.

The spelling of 52141225117642 in words is "fifty-two trillion, one hundred forty-one billion, two hundred twenty-five million, one hundred seventeen thousand, six hundred forty-two".

Divisors: 1 2 26070612558821 52141225117642