Base | Representation |
---|---|
bin | 10111101101110010111001… |
… | …10101000100110000001011 |
3 | 20211122120222100211200000112 |
4 | 23312321130311010300023 |
5 | 23313420322340400003 |
6 | 302525510051024535 |
7 | 13661534433461360 |
oct | 1366713465046013 |
9 | 224576870750015 |
10 | 52151050325003 |
11 | 15687155373813 |
12 | 5a2328129b14b |
13 | 2313a91013c86 |
14 | cc41a5136467 |
15 | 60687da3e3d8 |
hex | 2f6e5cd44c0b |
52151050325003 has 4 divisors (see below), whose sum is σ = 59601200371440. Its totient is φ = 44700900278568.
The previous prime is 52151050324993. The next prime is 52151050325009. The reversal of 52151050325003 is 30052305015125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52151050325003 - 240 = 51051538697227 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52151050325009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3725075023208 + ... + 3725075023221.
It is an arithmetic number, because the mean of its divisors is an integer number (14900300092860).
Almost surely, 252151050325003 is an apocalyptic number.
52151050325003 is a deficient number, since it is larger than the sum of its proper divisors (7450150046437).
52151050325003 is an equidigital number, since it uses as much as digits as its factorization.
52151050325003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7450150046436.
The product of its (nonzero) digits is 22500, while the sum is 32.
The spelling of 52151050325003 in words is "fifty-two trillion, one hundred fifty-one billion, fifty million, three hundred twenty-five thousand, three".
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