Base | Representation |
---|---|
bin | 10111101101110110101110… |
… | …00000111011100010101001 |
3 | 20211122210021020010211001202 |
4 | 23312323113000323202221 |
5 | 23313434022131101403 |
6 | 302530445320053545 |
7 | 13661636304542021 |
oct | 1366732700734251 |
9 | 224583236124052 |
10 | 52153100253353 |
11 | 15688007512280 |
12 | 5a237539042b5 |
13 | 231402991cc28 |
14 | cc431b4aaa81 |
15 | 60694d9b5688 |
hex | 2f6ed703b8a9 |
52153100253353 has 8 divisors (see below), whose sum is σ = 58856163295680. Its totient is φ = 45777015896080.
The previous prime is 52153100253349. The next prime is 52153100253389. The reversal of 52153100253353 is 35335200135125.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52153100253353 - 22 = 52153100253349 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52153100253323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81744670925 + ... + 81744671562.
It is an arithmetic number, because the mean of its divisors is an integer number (7357020411960).
Almost surely, 252153100253353 is an apocalyptic number.
It is an amenable number.
52153100253353 is a deficient number, since it is larger than the sum of its proper divisors (6703063042327).
52153100253353 is a wasteful number, since it uses less digits than its factorization.
52153100253353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163489342527.
The product of its (nonzero) digits is 202500, while the sum is 38.
Adding to 52153100253353 its reverse (35335200135125), we get a palindrome (87488300388478).
The spelling of 52153100253353 in words is "fifty-two trillion, one hundred fifty-three billion, one hundred million, two hundred fifty-three thousand, three hundred fifty-three".
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