Base | Representation |
---|---|
bin | 110000101000101000… |
… | …001000001001100111 |
3 | 11222210101102121020111 |
4 | 300220220020021213 |
5 | 1323422112342320 |
6 | 35553505513451 |
7 | 3526043002132 |
oct | 605050101147 |
9 | 158711377214 |
10 | 52221215335 |
11 | 20168573003 |
12 | a154942887 |
13 | 4c02cbba23 |
14 | 2755731219 |
15 | 15598a2a5a |
hex | c28a08267 |
52221215335 has 4 divisors (see below), whose sum is σ = 62665458408. Its totient is φ = 41776972264.
The previous prime is 52221215279. The next prime is 52221215341. The reversal of 52221215335 is 53351212225.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52221215335 - 223 = 52212826727 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52221215297 and 52221215306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5222121529 + ... + 5222121538.
It is an arithmetic number, because the mean of its divisors is an integer number (15666364602).
Almost surely, 252221215335 is an apocalyptic number.
52221215335 is a deficient number, since it is larger than the sum of its proper divisors (10444243073).
52221215335 is a wasteful number, since it uses less digits than its factorization.
52221215335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10444243072.
The product of its digits is 18000, while the sum is 31.
The spelling of 52221215335 in words is "fifty-two billion, two hundred twenty-one million, two hundred fifteen thousand, three hundred thirty-five".
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