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5230140433 = 7747162919
BaseRepresentation
bin1001101111011110…
…11001110000010001
3111111111102122212221
410313233121300101
541202403443213
62222552021041
7243415313560
oct46757316021
914444378787
105230140433
112244306a11
12101b691781
13654739a6b
1437888bbd7
1520926638d
hex137bd9c11

5230140433 has 4 divisors (see below), whose sum is σ = 5977303360. Its totient is φ = 4482977508.

The previous prime is 5230140403. The next prime is 5230140451. The reversal of 5230140433 is 3340410325.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5230140433 - 221 = 5228043281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5230140398 and 5230140407.

It is not an unprimeable number, because it can be changed into a prime (5230140403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373581453 + ... + 373581466.

It is an arithmetic number, because the mean of its divisors is an integer number (1494325840).

Almost surely, 25230140433 is an apocalyptic number.

It is an amenable number.

5230140433 is a deficient number, since it is larger than the sum of its proper divisors (747162927).

5230140433 is an equidigital number, since it uses as much as digits as its factorization.

5230140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 747162926.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 5230140433 is about 72319.7098514644. The cubic root of 5230140433 is about 1735.8190490436.

Adding to 5230140433 its reverse (3340410325), we get a palindrome (8570550758).

The spelling of 5230140433 in words is "five billion, two hundred thirty million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 7 747162919 5230140433