Base | Representation |
---|---|
bin | 110000101110100111… |
… | …001000011100100111 |
3 | 12000001101100120101201 |
4 | 300232213020130213 |
5 | 1324123313231303 |
6 | 40011453503331 |
7 | 3531402261325 |
oct | 605647103447 |
9 | 160041316351 |
10 | 52321617703 |
11 | 2020a209873 |
12 | a1824a1b47 |
13 | 4c1aa43704 |
14 | 2764bc8d15 |
15 | 15635d681d |
hex | c2e9c8727 |
52321617703 has 4 divisors (see below), whose sum is σ = 53058541968. Its totient is φ = 51584693440.
The previous prime is 52321617683. The next prime is 52321617709. The reversal of 52321617703 is 30771612325.
52321617703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52321617703 - 25 = 52321617671 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52321617709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368462026 + ... + 368462167.
It is an arithmetic number, because the mean of its divisors is an integer number (13264635492).
Almost surely, 252321617703 is an apocalyptic number.
52321617703 is a deficient number, since it is larger than the sum of its proper divisors (736924265).
52321617703 is an equidigital number, since it uses as much as digits as its factorization.
52321617703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 736924264.
The product of its (nonzero) digits is 52920, while the sum is 37.
The spelling of 52321617703 in words is "fifty-two billion, three hundred twenty-one million, six hundred seventeen thousand, seven hundred three".
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