Base | Representation |
---|---|
bin | 10111110011010101101101… |
… | …00011011011111000100111 |
3 | 20212022210122111212201001020 |
4 | 23321222312203123320213 |
5 | 23330030430224232443 |
6 | 303153211401502223 |
7 | 14011360004006526 |
oct | 1371526643337047 |
9 | 225283574781036 |
10 | 52341534211623 |
11 | 1574aa135810a8 |
12 | 5a54181aa1973 |
13 | 2328a29978717 |
14 | ccd4b54544bd |
15 | 60b7cb839583 |
hex | 2f9ab68dbe27 |
52341534211623 has 4 divisors (see below), whose sum is σ = 69788712282168. Its totient is φ = 34894356141080.
The previous prime is 52341534211559. The next prime is 52341534211627. The reversal of 52341534211623 is 32611243514325.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52341534211623 - 26 = 52341534211559 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52341534211627) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8723589035268 + ... + 8723589035273.
It is an arithmetic number, because the mean of its divisors is an integer number (17447178070542).
Almost surely, 252341534211623 is an apocalyptic number.
52341534211623 is a deficient number, since it is larger than the sum of its proper divisors (17447178070545).
52341534211623 is a wasteful number, since it uses less digits than its factorization.
52341534211623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17447178070544.
The product of its digits is 518400, while the sum is 42.
Adding to 52341534211623 its reverse (32611243514325), we get a palindrome (84952777725948).
The spelling of 52341534211623 in words is "fifty-two trillion, three hundred forty-one billion, five hundred thirty-four million, two hundred eleven thousand, six hundred twenty-three".
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