Base | Representation |
---|---|
bin | 100110000101011010010… |
… | …1011101101101001000111 |
3 | 200112101122110202210122211 |
4 | 1030022310223231221013 |
5 | 1141224322142241201 |
6 | 15044334355204251 |
7 | 1050110604600661 |
oct | 114126453555107 |
9 | 20471573683584 |
10 | 5234301524551 |
11 | 1738944830860 |
12 | 706538ba6687 |
13 | 2bc7919ac918 |
14 | 1414ad2b5531 |
15 | 91252255651 |
hex | 4c2b4aeda47 |
5234301524551 has 8 divisors (see below), whose sum is σ = 5907048742800. Its totient is φ = 4594371243840.
The previous prime is 5234301524479. The next prime is 5234301524567. The reversal of 5234301524551 is 1554251034325.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5234301524551 - 223 = 5234293135943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5234301524581) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8204234046 + ... + 8204234683.
It is an arithmetic number, because the mean of its divisors is an integer number (738381092850).
Almost surely, 25234301524551 is an apocalyptic number.
5234301524551 is a deficient number, since it is larger than the sum of its proper divisors (672747218249).
5234301524551 is a wasteful number, since it uses less digits than its factorization.
5234301524551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16408468769.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 5234301524551 its reverse (1554251034325), we get a palindrome (6788552558876).
The spelling of 5234301524551 in words is "five trillion, two hundred thirty-four billion, three hundred one million, five hundred twenty-four thousand, five hundred fifty-one".
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