Base | Representation |
---|---|
bin | 110000110101010011… |
… | …110101100111010111 |
3 | 12000100012211012101201 |
4 | 300311103311213113 |
5 | 1324341101002333 |
6 | 40030550333331 |
7 | 3534235435444 |
oct | 606523654727 |
9 | 160305735351 |
10 | 52434000343 |
11 | 2026769858a |
12 | a1b405a247 |
13 | 4c3810140a |
14 | 2775ac09cb |
15 | 156d3d517d |
hex | c354f59d7 |
52434000343 has 4 divisors (see below), whose sum is σ = 52539079000. Its totient is φ = 52328921688.
The previous prime is 52434000341. The next prime is 52434000347. The reversal of 52434000343 is 34300043425.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52434000343 - 21 = 52434000341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52434000341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52538580 + ... + 52539577.
It is an arithmetic number, because the mean of its divisors is an integer number (13134769750).
Almost surely, 252434000343 is an apocalyptic number.
52434000343 is a deficient number, since it is larger than the sum of its proper divisors (105078657).
52434000343 is a wasteful number, since it uses less digits than its factorization.
52434000343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105078656.
The product of its (nonzero) digits is 17280, while the sum is 28.
Adding to 52434000343 its reverse (34300043425), we get a palindrome (86734043768).
The spelling of 52434000343 in words is "fifty-two billion, four hundred thirty-four million, three hundred forty-three", and thus it is an aban number.
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