Base | Representation |
---|---|
bin | 10111110110000100110010… |
… | …01101111100101011000001 |
3 | 20212122210021100000120001121 |
4 | 23323002121031330223001 |
5 | 23333100432004220001 |
6 | 303304314530032241 |
7 | 14021225230154344 |
oct | 1373023115745301 |
9 | 225583240016047 |
10 | 52435531320001 |
11 | 15786869490945 |
12 | 5a6a435418681 |
13 | 233485991918b |
14 | cd3c7115245b |
15 | 60de7da696a1 |
hex | 2fb09937cac1 |
52435531320001 has 8 divisors (see below), whose sum is σ = 52522832433344. Its totient is φ = 52348273166160.
The previous prime is 52435531319981. The next prime is 52435531320017. The reversal of 52435531320001 is 10002313553425.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 52435531320001 - 215 = 52435531287233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52435531320071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8296221 + ... + 13179466.
It is an arithmetic number, because the mean of its divisors is an integer number (6565354054168).
Almost surely, 252435531320001 is an apocalyptic number.
It is an amenable number.
52435531320001 is a deficient number, since it is larger than the sum of its proper divisors (87301113343).
52435531320001 is a wasteful number, since it uses less digits than its factorization.
52435531320001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21479751.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 52435531320001 its reverse (10002313553425), we get a palindrome (62437844873426).
The spelling of 52435531320001 in words is "fifty-two trillion, four hundred thirty-five billion, five hundred thirty-one million, three hundred twenty thousand, one".
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