52500134410035 has 64 divisors (see below), whose sum is σ = 93683874170880. Its totient is φ = 24927575662080.

The previous prime is 52500134410027. The next prime is 52500134410043. The reversal of 52500134410035 is 53001443100525.

It is an interprime number because it is at equal distance from previous prime (52500134410027) and next prime (52500134410043).

It is not a de Polignac number, because 52500134410035 - 2³ = 52500134410027 is a prime.

It is a super-3 number, since 3×52500134410035³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 52500134409978 and 52500134410005.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 56292 + ... + 10247118.

It is an arithmetic number, because the mean of its divisors is an integer number (1463810533920).

Almost surely, 2^{52500134410035} is an apocalyptic number.

52500134410035 is a deficient number, since it is larger than the sum of its proper divisors (41183739760845).

52500134410035 is a wasteful number, since it uses less digits than its factorization.

52500134410035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10191788.

The product of its (nonzero) digits is 36000, while the sum is 33.

The spelling of 52500134410035 in words is "fifty-two trillion, five hundred billion, one hundred thirty-four million, four hundred ten thousand, thirty-five".