Base | Representation |
---|---|
bin | 100110001100101111101… |
… | …1001011000100001000101 |
3 | 200120220022001021221011010 |
4 | 1030121133121120201011 |
5 | 1142004100413302003 |
6 | 15055501231032433 |
7 | 1051206101104632 |
oct | 114313731304105 |
9 | 20526261257133 |
10 | 5250050525253 |
11 | 1744596720116 |
12 | 7095b336b719 |
13 | 2c1101763651 |
14 | 142164b8b189 |
15 | 91874bbb003 |
hex | 4c65f658845 |
5250050525253 has 4 divisors (see below), whose sum is σ = 7000067367008. Its totient is φ = 3500033683500.
The previous prime is 5250050525047. The next prime is 5250050525311. The reversal of 5250050525253 is 3525250500525.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 5250050525253 - 230 = 5248976783429 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5250050425253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875008420873 + ... + 875008420878.
It is an arithmetic number, because the mean of its divisors is an integer number (1750016841752).
Almost surely, 25250050525253 is an apocalyptic number.
It is an amenable number.
5250050525253 is a deficient number, since it is larger than the sum of its proper divisors (1750016841755).
5250050525253 is a wasteful number, since it uses less digits than its factorization.
5250050525253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1750016841754.
The product of its (nonzero) digits is 375000, while the sum is 39.
The spelling of 5250050525253 in words is "five trillion, two hundred fifty billion, fifty million, five hundred twenty-five thousand, two hundred fifty-three".
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