Base | Representation |
---|---|
bin | 100110001100110011101… |
… | …0010001011100010001101 |
3 | 200120220122021021222011100 |
4 | 1030121213102023202031 |
5 | 1142004333302323142 |
6 | 15055522315213313 |
7 | 1051212265640226 |
oct | 114314722134215 |
9 | 20526567258140 |
10 | 5250182854797 |
11 | 1744654393281 |
12 | 70962b747239 |
13 | 2c1122cb655a |
14 | 14217859624d |
15 | 91881609b4c |
hex | 4c66748b88d |
5250182854797 has 12 divisors (see below), whose sum is σ = 7583635674940. Its totient is φ = 3500104264128.
The previous prime is 5250182854769. The next prime is 5250182854817. The reversal of 5250182854797 is 7974582810525.
5250182854797 is a `hidden beast` number, since 5 + 2 + 5 + 0 + 1 + 82 + 8 + 547 + 9 + 7 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 3376648804356 + 1873534050441 = 1837566^2 + 1368771^2 .
It is not a de Polignac number, because 5250182854797 - 27 = 5250182854669 is a prime.
It is a super-2 number, since 2×52501828547972 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5250182854997) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 563163 + ... + 3288999.
Almost surely, 25250182854797 is an apocalyptic number.
It is an amenable number.
5250182854797 is a deficient number, since it is larger than the sum of its proper divisors (2333452820143).
5250182854797 is a wasteful number, since it uses less digits than its factorization.
5250182854797 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2939852 (or 2939849 counting only the distinct ones).
The product of its (nonzero) digits is 56448000, while the sum is 63.
The spelling of 5250182854797 in words is "five trillion, two hundred fifty billion, one hundred eighty-two million, eight hundred fifty-four thousand, seven hundred ninety-seven".
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