Base | Representation |
---|---|
bin | 1111010001111100100… |
… | …00100111010010110001 |
3 | 1212012012021121112112220 |
4 | 13220332100213102301 |
5 | 32100230310142003 |
6 | 1041110134511253 |
7 | 52634514030660 |
oct | 7507620472261 |
9 | 1765167545486 |
10 | 525030552753 |
11 | 192734072233 |
12 | 85907805529 |
13 | 3a682ac0a35 |
14 | 1b5a9680dd7 |
15 | d9cd33d353 |
hex | 7a3e4274b1 |
525030552753 has 32 divisors (see below), whose sum is σ = 842206464000. Its totient is φ = 284209451136.
The previous prime is 525030552749. The next prime is 525030552757. The reversal of 525030552753 is 357255030525.
525030552753 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (525030552749) and next prime (525030552757).
It is not a de Polignac number, because 525030552753 - 22 = 525030552749 is a prime.
It is a super-3 number, since 3×5250305527533 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (525030552757) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8809348 + ... + 8868746.
It is an arithmetic number, because the mean of its divisors is an integer number (26318952000).
Almost surely, 2525030552753 is an apocalyptic number.
It is an amenable number.
525030552753 is a deficient number, since it is larger than the sum of its proper divisors (317175911247).
525030552753 is a wasteful number, since it uses less digits than its factorization.
525030552753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81581.
The product of its (nonzero) digits is 787500, while the sum is 42.
The spelling of 525030552753 in words is "five hundred twenty-five billion, thirty million, five hundred fifty-two thousand, seven hundred fifty-three".
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