Base | Representation |
---|---|
bin | 10111111000000010101100… |
… | …10101110001110110110001 |
3 | 20212220020202022120010022020 |
4 | 23330001112111301312301 |
5 | 23340202401431313423 |
6 | 303355334314102053 |
7 | 14026140322104021 |
oct | 1374012625616661 |
9 | 225806668503266 |
10 | 52503128776113 |
11 | 158024a7493154 |
12 | 5a7b55b71a929 |
13 | 233b040397012 |
14 | cd7244a45a81 |
15 | 610ad82a04e3 |
hex | 2fc056571db1 |
52503128776113 has 32 divisors (see below), whose sum is σ = 70261952217600. Its totient is φ = 34873403316480.
The previous prime is 52503128776081. The next prime is 52503128776121. The reversal of 52503128776113 is 31167782130525.
It is not a de Polignac number, because 52503128776113 - 25 = 52503128776081 is a prime.
It is a super-2 number, since 2×525031287761132 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (52503128776513) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5825262195 + ... + 5825271207.
It is an arithmetic number, because the mean of its divisors is an integer number (2195686006800).
Almost surely, 252503128776113 is an apocalyptic number.
It is an amenable number.
52503128776113 is a deficient number, since it is larger than the sum of its proper divisors (17758823441487).
52503128776113 is a wasteful number, since it uses less digits than its factorization.
52503128776113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14009.
The product of its (nonzero) digits is 2116800, while the sum is 51.
The spelling of 52503128776113 in words is "fifty-two trillion, five hundred three billion, one hundred twenty-eight million, seven hundred seventy-six thousand, one hundred thirteen".
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