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5250530528057 = 19276343712003
BaseRepresentation
bin100110001100111110000…
…0000011100101100111001
3200120221112111111121012202
41030121330000130230321
51142011041303344212
615100021015115545
71051224020054003
oct114317400345471
920527474447182
105250530528057
111744812669351
12709708072bb5
132c117a036689
141421ac819373
15918a1dd40c2
hex4c67c01cb39

5250530528057 has 4 divisors (see below), whose sum is σ = 5526874240080. Its totient is φ = 4974186816036.

The previous prime is 5250530528053. The next prime is 5250530528063. The reversal of 5250530528057 is 7508250350525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5250530528057 - 22 = 5250530528053 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5250530528053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138171855983 + ... + 138171856020.

It is an arithmetic number, because the mean of its divisors is an integer number (1381718560020).

Almost surely, 25250530528057 is an apocalyptic number.

It is an amenable number.

5250530528057 is a deficient number, since it is larger than the sum of its proper divisors (276343712023).

5250530528057 is a wasteful number, since it uses less digits than its factorization.

5250530528057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 276343712022.

The product of its (nonzero) digits is 2100000, while the sum is 47.

The spelling of 5250530528057 in words is "five trillion, two hundred fifty billion, five hundred thirty million, five hundred twenty-eight thousand, fifty-seven".

Divisors: 1 19 276343712003 5250530528057