Base | Representation |
---|---|
bin | 110000111001110010… |
… | …000100110110101101 |
3 | 12000112110000101220020 |
4 | 300321302010312231 |
5 | 1330014303122244 |
6 | 40042230512353 |
7 | 3536136304236 |
oct | 607162046655 |
9 | 160473011806 |
10 | 52509035949 |
11 | 202a5a88987 |
12 | a2152056b9 |
13 | 4c4a813c96 |
14 | 2781a5408d |
15 | 1574ca7d19 |
hex | c39c84dad |
52509035949 has 16 divisors (see below), whose sum is σ = 76901107200. Its totient is φ = 31721705136.
The previous prime is 52509035941. The next prime is 52509035963. The reversal of 52509035949 is 94953090525.
52509035949 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 52509035949 - 23 = 52509035941 is a prime.
It is a super-3 number, since 3×525090359493 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52509035941) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20025019 + ... + 20027640.
It is an arithmetic number, because the mean of its divisors is an integer number (4806319200).
Almost surely, 252509035949 is an apocalyptic number.
It is an amenable number.
52509035949 is a deficient number, since it is larger than the sum of its proper divisors (24392071251).
52509035949 is a wasteful number, since it uses less digits than its factorization.
52509035949 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40052704.
The product of its (nonzero) digits is 2187000, while the sum is 51.
The spelling of 52509035949 in words is "fifty-two billion, five hundred nine million, thirty-five thousand, nine hundred forty-nine".
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