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5251240151 = 41113127727
BaseRepresentation
bin1001110001111111…
…11001000011010111
3111112222010122020222
410320333321003113
541223304141101
62225024144555
7244062543023
oct47077710327
914488118228
105251240151
1122552084a3
12102676815b
13658c168c1
1437b5c1383
1520b03301b
hex138ff90d7

5251240151 has 4 divisors (see below), whose sum is σ = 5251408992. Its totient is φ = 5251071312.

The previous prime is 5251240139. The next prime is 5251240153. The reversal of 5251240151 is 1510421525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5251240151 - 214 = 5251223767 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5251240151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5251240153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22751 + ... + 104976.

It is an arithmetic number, because the mean of its divisors is an integer number (1312852248).

Almost surely, 25251240151 is an apocalyptic number.

5251240151 is a deficient number, since it is larger than the sum of its proper divisors (168841).

5251240151 is a wasteful number, since it uses less digits than its factorization.

5251240151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168840.

The product of its (nonzero) digits is 2000, while the sum is 26.

The square root of 5251240151 is about 72465.4410805592. The cubic root of 5251240151 is about 1738.1501623967.

Adding to 5251240151 its reverse (1510421525), we get a palindrome (6761661676).

The spelling of 5251240151 in words is "five billion, two hundred fifty-one million, two hundred forty thousand, one hundred fifty-one".

Divisors: 1 41113 127727 5251240151