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52512550413 = 317504183471
BaseRepresentation
bin110000111001111111…
…011110111000001101
312000112200121221211120
4300321333132320031
51330021203103123
640042434111153
73536211212421
oct607177367015
9160480557746
1052512550413
11202a7a693a4
12a21641b4b9
134c4b47484b
1427822cab81
15157524e2e3
hexc39fdee0d

52512550413 has 4 divisors (see below), whose sum is σ = 70016733888. Its totient is φ = 35008366940.

The previous prime is 52512550411. The next prime is 52512550421. The reversal of 52512550413 is 31405521525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52512550413 - 21 = 52512550411 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52512550411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8752091733 + ... + 8752091738.

It is an arithmetic number, because the mean of its divisors is an integer number (17504183472).

Almost surely, 252512550413 is an apocalyptic number.

It is an amenable number.

52512550413 is a deficient number, since it is larger than the sum of its proper divisors (17504183475).

52512550413 is a wasteful number, since it uses less digits than its factorization.

52512550413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17504183474.

The product of its (nonzero) digits is 30000, while the sum is 33.

The spelling of 52512550413 in words is "fifty-two billion, five hundred twelve million, five hundred fifty thousand, four hundred thirteen".

Divisors: 1 3 17504183471 52512550413