Base | Representation |
---|---|
bin | 100110001101101011010… |
… | …0101100011001010101011 |
3 | 200121002110102001002202021 |
4 | 1030123112211203022223 |
5 | 1142022144323001212 |
6 | 15100431503045311 |
7 | 1051306462066045 |
oct | 114332645431253 |
9 | 20532412032667 |
10 | 5252050203307 |
11 | 1745422467906 |
12 | 709a70ba0837 |
13 | 2c135cb272bb |
14 | 1422b45a0a95 |
15 | 91940518307 |
hex | 4c6d69632ab |
5252050203307 has 8 divisors (see below), whose sum is σ = 5254626004992. Its totient is φ = 5249474697000.
The previous prime is 5252050203299. The next prime is 5252050203373. The reversal of 5252050203307 is 7033020502525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5252050203307 - 23 = 5252050203299 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5252050203007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41010388 + ... + 41138254.
It is an arithmetic number, because the mean of its divisors is an integer number (656828250624).
Almost surely, 25252050203307 is an apocalyptic number.
5252050203307 is a deficient number, since it is larger than the sum of its proper divisors (2575801685).
5252050203307 is a wasteful number, since it uses less digits than its factorization.
5252050203307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147689.
The product of its (nonzero) digits is 63000, while the sum is 34.
The spelling of 5252050203307 in words is "five trillion, two hundred fifty-two billion, fifty million, two hundred three thousand, three hundred seven".
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