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52521103423 = 149352490627
BaseRepresentation
bin110000111010100000…
…000111000000111111
312000120021201111100201
4300322200013000333
51330030400302143
640043341304331
73536344004335
oct607240070077
9160507644321
1052521103423
11203018803a8
12a2192650a7
134c5017a8b9
1427834b5b55
151575d8d64d
hexc3a80703f

52521103423 has 4 divisors (see below), whose sum is σ = 52873594200. Its totient is φ = 52168612648.

The previous prime is 52521103417. The next prime is 52521103447. The reversal of 52521103423 is 32430112525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52521103423 - 25 = 52521103391 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52521103391 and 52521103400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52521103463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176245165 + ... + 176245462.

It is an arithmetic number, because the mean of its divisors is an integer number (13218398550).

Almost surely, 252521103423 is an apocalyptic number.

52521103423 is a deficient number, since it is larger than the sum of its proper divisors (352490777).

52521103423 is a wasteful number, since it uses less digits than its factorization.

52521103423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 352490776.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 52521103423 its reverse (32430112525), we get a palindrome (84951215948).

The spelling of 52521103423 in words is "fifty-two billion, five hundred twenty-one million, one hundred three thousand, four hundred twenty-three".

Divisors: 1 149 352490627 52521103423