Base | Representation |
---|---|
bin | 1001110010001000… |
… | …01001100101110111 |
3 | 111120001020100120011 |
4 | 10321010021211313 |
5 | 41224100401341 |
6 | 2225104121051 |
7 | 244105202425 |
oct | 47104114567 |
9 | 14501210504 |
10 | 5252356471 |
11 | 225590017a |
12 | 1027006187 |
13 | 659217a4b |
14 | 37b7d2115 |
15 | 20b1a3b81 |
hex | 139109977 |
5252356471 has 4 divisors (see below), whose sum is σ = 5269465432. Its totient is φ = 5235247512.
The previous prime is 5252356457. The next prime is 5252356507. The reversal of 5252356471 is 1746532525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5252356471 - 213 = 5252348279 is a prime.
It is a super-3 number, since 3×52523564713 (a number of 30 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5252356451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8554020 + ... + 8554633.
It is an arithmetic number, because the mean of its divisors is an integer number (1317366358).
Almost surely, 25252356471 is an apocalyptic number.
5252356471 is a deficient number, since it is larger than the sum of its proper divisors (17108961).
5252356471 is a wasteful number, since it uses less digits than its factorization.
5252356471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17108960.
The product of its digits is 252000, while the sum is 40.
The square root of 5252356471 is about 72473.1431014276. The cubic root of 5252356471 is about 1738.2733202449.
Adding to 5252356471 its reverse (1746532525), we get a palindrome (6998888996).
The spelling of 5252356471 in words is "five billion, two hundred fifty-two million, three hundred fifty-six thousand, four hundred seventy-one".
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