Base | Representation |
---|---|
bin | 110000111010101111… |
… | …111000011001010111 |
3 | 12000120120111112201112 |
4 | 300322233320121113 |
5 | 1330032430102342 |
6 | 40044010045235 |
7 | 3536424104135 |
oct | 607257703127 |
9 | 160516445645 |
10 | 52525237847 |
11 | 20304144685 |
12 | a21a71981b |
13 | 4c50c976c4 |
14 | 2783c70755 |
15 | 1576408682 |
hex | c3abf8657 |
52525237847 has 4 divisors (see below), whose sum is σ = 52553223336. Its totient is φ = 52497252360.
The previous prime is 52525237829. The next prime is 52525237861. The reversal of 52525237847 is 74873252525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52525237847 - 210 = 52525236823 is a prime.
It is a super-3 number, since 3×525252378473 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52525237795 and 52525237804.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52525237147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13989929 + ... + 13993682.
It is an arithmetic number, because the mean of its divisors is an integer number (13138305834).
Almost surely, 252525237847 is an apocalyptic number.
52525237847 is a deficient number, since it is larger than the sum of its proper divisors (27985489).
52525237847 is a wasteful number, since it uses less digits than its factorization.
52525237847 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27985488.
The product of its digits is 4704000, while the sum is 50.
The spelling of 52525237847 in words is "fifty-two billion, five hundred twenty-five million, two hundred thirty-seven thousand, eight hundred forty-seven".
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