Base | Representation |
---|---|
bin | 111011101110001110110100… |
… | …1011100101000101001001100 |
3 | 2112220000102210220221002001112 |
4 | 1313130131221130220221030 |
5 | 1022323400024044231434 |
6 | 5101134142445231152 |
7 | 215436241253030252 |
oct | 16734355134505114 |
9 | 2486012726832045 |
10 | 525323514055244 |
11 | 1424254a658a373 |
12 | 4ab03271b624b8 |
13 | 19717a44293128 |
14 | 93a1b180645d2 |
15 | 40aed0bb66dce |
hex | 1ddc769728a4c |
525323514055244 has 12 divisors (see below), whose sum is σ = 925486056642000. Its totient is φ = 260898926443248.
The previous prime is 525323514055229. The next prime is 525323514055267. The reversal of 525323514055244 is 442550415323525.
It is a super-3 number, since 3×5253235140552443 (a number of 45 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 525323514055192 and 525323514055201.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 440707645424 + ... + 440707646615.
It is an arithmetic number, because the mean of its divisors is an integer number (77123838053500).
Almost surely, 2525323514055244 is an apocalyptic number.
It is an amenable number.
525323514055244 is a deficient number, since it is larger than the sum of its proper divisors (400162542586756).
525323514055244 is a wasteful number, since it uses less digits than its factorization.
525323514055244 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 881415292192 (or 881415292190 counting only the distinct ones).
The product of its (nonzero) digits is 14400000, while the sum is 50.
Adding to 525323514055244 its reverse (442550415323525), we get a palindrome (967873929378769).
The spelling of 525323514055244 in words is "five hundred twenty-five trillion, three hundred twenty-three billion, five hundred fourteen million, fifty-five thousand, two hundred forty-four".
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