Base | Representation |
---|---|
bin | 10111111000111011100011… |
… | …11010000110001110100101 |
3 | 20220000011112211000110002210 |
4 | 23330131301322012032211 |
5 | 23341202411422141040 |
6 | 303421343423354033 |
7 | 14031300653503155 |
oct | 1374356172061645 |
9 | 226004484013083 |
10 | 52533656052645 |
11 | 15814442323909 |
12 | 5a8545b152919 |
13 | 2340b96a74661 |
14 | cd88dd106765 |
15 | 6117c332e480 |
hex | 2fc771e863a5 |
52533656052645 has 16 divisors (see below), whose sum is σ = 84053985420672. Its totient is φ = 28017904649280.
The previous prime is 52533656052643. The next prime is 52533656052667. The reversal of 52533656052645 is 54625065633525.
It is not a de Polignac number, because 52533656052645 - 21 = 52533656052643 is a prime.
It is a super-2 number, since 2×525336560526452 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52533656052643) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8143539 + ... + 13091391.
It is an arithmetic number, because the mean of its divisors is an integer number (5253374088792).
Almost surely, 252533656052645 is an apocalyptic number.
It is an amenable number.
52533656052645 is a deficient number, since it is larger than the sum of its proper divisors (31520329368027).
52533656052645 is a wasteful number, since it uses less digits than its factorization.
52533656052645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5655692.
The product of its (nonzero) digits is 97200000, while the sum is 57.
The spelling of 52533656052645 in words is "fifty-two trillion, five hundred thirty-three billion, six hundred fifty-six million, fifty-two thousand, six hundred forty-five".
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