Search a number
-
+
52533661237 = 349811501777
BaseRepresentation
bin110000111011010000…
…000000111000110101
312000121011100111102221
4300323100000320311
51330042104124422
640044510402341
73536555516131
oct607320007065
9160534314387
1052533661237
1120308978262
12a2215003b1
134c52956765
1427850243c1
15157701e3c7
hexc3b400e35

52533661237 has 4 divisors (see below), whose sum is σ = 52535197996. Its totient is φ = 52532124480.

The previous prime is 52533661217. The next prime is 52533661291. The reversal of 52533661237 is 73216633525.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12453220836 + 40080440401 = 111594^2 + 200201^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52533661237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52533661193 and 52533661202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52533661217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715908 + ... + 785869.

It is an arithmetic number, because the mean of its divisors is an integer number (13133799499).

Almost surely, 252533661237 is an apocalyptic number.

It is an amenable number.

52533661237 is a deficient number, since it is larger than the sum of its proper divisors (1536759).

52533661237 is a wasteful number, since it uses less digits than its factorization.

52533661237 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1536758.

The product of its digits is 680400, while the sum is 43.

The spelling of 52533661237 in words is "fifty-two billion, five hundred thirty-three million, six hundred sixty-one thousand, two hundred thirty-seven".

Divisors: 1 34981 1501777 52533661237