Base | Representation |
---|---|
bin | 100110001110010011100… |
… | …1011011010011111100111 |
3 | 200121012221122021001200121 |
4 | 1030130213023122133213 |
5 | 1142032431442302120 |
6 | 15101214003222411 |
7 | 1051355130554005 |
oct | 114344713323747 |
9 | 20535848231617 |
10 | 5253402306535 |
11 | 1745a56711a99 |
12 | 70a189977a07 |
13 | 2c1516ca5a96 |
14 | 1423a1da5a75 |
15 | 919be09b5aa |
hex | 4c7272da7e7 |
5253402306535 has 4 divisors (see below), whose sum is σ = 6304082767848. Its totient is φ = 4202721845224.
The previous prime is 5253402306521. The next prime is 5253402306557. The reversal of 5253402306535 is 5356032043525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5253402306535 - 27 = 5253402306407 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5253402306491 and 5253402306500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 525340230649 + ... + 525340230658.
It is an arithmetic number, because the mean of its divisors is an integer number (1576020691962).
Almost surely, 25253402306535 is an apocalyptic number.
5253402306535 is a deficient number, since it is larger than the sum of its proper divisors (1050680461313).
5253402306535 is a wasteful number, since it uses less digits than its factorization.
5253402306535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1050680461312.
The product of its (nonzero) digits is 1620000, while the sum is 43.
The spelling of 5253402306535 in words is "five trillion, two hundred fifty-three billion, four hundred two million, three hundred six thousand, five hundred thirty-five".
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