Base | Representation |
---|---|
bin | 10111111000111100011001… |
… | …01011011110001000110101 |
3 | 20220000012201010011122220111 |
4 | 23330132030223132020311 |
5 | 23341204321413001003 |
6 | 303421500150303021 |
7 | 14031315046304152 |
oct | 1374361453361065 |
9 | 226005633148814 |
10 | 52534105203253 |
11 | 1581465290a363 |
12 | 5a85565657a71 |
13 | 2340c38b3484b |
14 | cd8942a23229 |
15 | 6117ec9a0e6d |
hex | 2fc78cade235 |
52534105203253 has 16 divisors (see below), whose sum is σ = 55196973336960. Its totient is φ = 49947034954176.
The previous prime is 52534105203191. The next prime is 52534105203259. The reversal of 52534105203253 is 35230250143525.
It is a cyclic number.
It is not a de Polignac number, because 52534105203253 - 29 = 52534105202741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52534105203259) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71686626 + ... + 72415747.
It is an arithmetic number, because the mean of its divisors is an integer number (3449810833560).
Almost surely, 252534105203253 is an apocalyptic number.
It is an amenable number.
52534105203253 is a deficient number, since it is larger than the sum of its proper divisors (2662868133707).
52534105203253 is a wasteful number, since it uses less digits than its factorization.
52534105203253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 144102636.
The product of its (nonzero) digits is 540000, while the sum is 40.
Adding to 52534105203253 its reverse (35230250143525), we get a palindrome (87764355346778).
The spelling of 52534105203253 in words is "fifty-two trillion, five hundred thirty-four billion, one hundred five million, two hundred three thousand, two hundred fifty-three".
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