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52535405413 = 478710974599
BaseRepresentation
bin110000111011010110…
…101010101101100101
312000121021122010000001
4300323112222231211
51330043030433123
640045012021301
73536606402161
oct607326525545
9160537563001
1052535405413
1120309959727
12a222001831
134c5311760a
142785359ca1
1515772660ad
hexc3b5aab65

52535405413 has 4 divisors (see below), whose sum is σ = 52546384800. Its totient is φ = 52524426028.

The previous prime is 52535405369. The next prime is 52535405437. The reversal of 52535405413 is 31450453525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52535405413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52535405113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5482513 + ... + 5492086.

It is an arithmetic number, because the mean of its divisors is an integer number (13136596200).

Almost surely, 252535405413 is an apocalyptic number.

It is an amenable number.

52535405413 is a deficient number, since it is larger than the sum of its proper divisors (10979387).

52535405413 is a wasteful number, since it uses less digits than its factorization.

52535405413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10979386.

The product of its (nonzero) digits is 180000, while the sum is 37.

Adding to 52535405413 its reverse (31450453525), we get a palindrome (83985858938).

The spelling of 52535405413 in words is "fifty-two billion, five hundred thirty-five million, four hundred five thousand, four hundred thirteen".

Divisors: 1 4787 10974599 52535405413