Base | Representation |
---|---|
bin | 10111111001000010000001… |
… | …00011011111011010100111 |
3 | 20220000111111102201010210201 |
4 | 23330201000203133122213 |
5 | 23341232011442311330 |
6 | 303423115432331331 |
7 | 14031452612243164 |
oct | 1374410043373247 |
9 | 226014442633721 |
10 | 52537123010215 |
11 | 158159613323a8 |
12 | 5a86068243b47 |
13 | 23412ca11223c |
14 | cd8b4b74306b |
15 | 6119278b0eca |
hex | 2fc8408df6a7 |
52537123010215 has 4 divisors (see below), whose sum is σ = 63044547612264. Its totient is φ = 42029698408168.
The previous prime is 52537123010209. The next prime is 52537123010279. The reversal of 52537123010215 is 51201032173525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52537123010215 - 29 = 52537123009703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5253712301017 + ... + 5253712301026.
It is an arithmetic number, because the mean of its divisors is an integer number (15761136903066).
Almost surely, 252537123010215 is an apocalyptic number.
52537123010215 is a deficient number, since it is larger than the sum of its proper divisors (10507424602049).
52537123010215 is a wasteful number, since it uses less digits than its factorization.
52537123010215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10507424602048.
The product of its (nonzero) digits is 63000, while the sum is 37.
The spelling of 52537123010215 in words is "fifty-two trillion, five hundred thirty-seven billion, one hundred twenty-three million, ten thousand, two hundred fifteen".
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