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52540131049 = 77505733007
BaseRepresentation
bin110000111011101000…
…101100011011101001
312000121121112012100121
4300323220230123221
51330100233143144
640045301203241
73536664513430
oct607350543351
9160547465317
1052540131049
112031159710a
12a223700521
134c540b0553
142785c2a117
15157789b384
hexc3ba2c6e9

52540131049 has 4 divisors (see below), whose sum is σ = 60045864064. Its totient is φ = 45034398036.

The previous prime is 52540130999. The next prime is 52540131067. The reversal of 52540131049 is 94013104525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52540131049 - 217 = 52539999977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52540135049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3752866497 + ... + 3752866510.

It is an arithmetic number, because the mean of its divisors is an integer number (15011466016).

Almost surely, 252540131049 is an apocalyptic number.

It is an amenable number.

52540131049 is a deficient number, since it is larger than the sum of its proper divisors (7505733015).

52540131049 is an equidigital number, since it uses as much as digits as its factorization.

52540131049 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7505733014.

The product of its (nonzero) digits is 21600, while the sum is 34.

The spelling of 52540131049 in words is "fifty-two billion, five hundred forty million, one hundred thirty-one thousand, forty-nine".

Divisors: 1 7 7505733007 52540131049