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52543044353 = 192765423387
BaseRepresentation
bin110000111011110011…
…110011101100000001
312000121211000012122202
4300323303303230001
51330102004404403
640045443442545
73540031336142
oct607363635401
9160554005582
1052543044353
11203131a69a8
12a224686455
134c548905b7
142786387ac9
151577c74688
hexc3bcf3b01

52543044353 has 4 divisors (see below), whose sum is σ = 55308467760. Its totient is φ = 49777620948.

The previous prime is 52543044313. The next prime is 52543044361. The reversal of 52543044353 is 35344034525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52543044353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52543044313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1382711675 + ... + 1382711712.

It is an arithmetic number, because the mean of its divisors is an integer number (13827116940).

Almost surely, 252543044353 is an apocalyptic number.

It is an amenable number.

52543044353 is a deficient number, since it is larger than the sum of its proper divisors (2765423407).

52543044353 is a wasteful number, since it uses less digits than its factorization.

52543044353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2765423406.

The product of its (nonzero) digits is 432000, while the sum is 38.

Adding to 52543044353 its reverse (35344034525), we get a palindrome (87887078878).

The spelling of 52543044353 in words is "fifty-two billion, five hundred forty-three million, forty-four thousand, three hundred fifty-three".

Divisors: 1 19 2765423387 52543044353