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52543134213 = 317514378071
BaseRepresentation
bin110000111011110100…
…001001101000000101
312000121211011202220220
4300323310021220011
51330102020243323
640045445414553
73540032162133
oct607364115005
9160554152826
1052543134213
1120313258469
12a22470a459
134c548c247b
1427863ac753
151577c910e3
hexc3bd09a05

52543134213 has 4 divisors (see below), whose sum is σ = 70057512288. Its totient is φ = 35028756140.

The previous prime is 52543134197. The next prime is 52543134221. The reversal of 52543134213 is 31243134525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52543134213 - 24 = 52543134197 is a prime.

It is a super-2 number, since 2×525431342132 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52543134253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8757189033 + ... + 8757189038.

It is an arithmetic number, because the mean of its divisors is an integer number (17514378072).

Almost surely, 252543134213 is an apocalyptic number.

It is an amenable number.

52543134213 is a deficient number, since it is larger than the sum of its proper divisors (17514378075).

52543134213 is a wasteful number, since it uses less digits than its factorization.

52543134213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17514378074.

The product of its digits is 43200, while the sum is 33.

Adding to 52543134213 its reverse (31243134525), we get a palindrome (83786268738).

The spelling of 52543134213 in words is "fifty-two billion, five hundred forty-three million, one hundred thirty-four thousand, two hundred thirteen".

Divisors: 1 3 17514378071 52543134213